Dice Roller and Tag Testing Thread - Five (5) Post Limit!

[Anodyzed]

Mine is a question more than a comment.

We Shadowrun players sometimes need 'exploding die' meaning that we roll multiple d6s. Any 5 or 6 is a 'hit', and if a 6 comes up, we want THAT 6 to be rerolled, so it might get us another 'hit,' and we want that rerolling of sixes to continue until there are no more hits.
Without the exploding die, the tag looks like this (inside the dice tags): 12d6smch5

I can't from the directions in the die rolling faq figure out how to put the exploding sixes on the end of that and make it acutally work. Anyone have the solution to that??

[JorvikDave]

Dice Test Attack:

d20+5

(20)+5

Total = 25

Dice Base Damage:

2d8+5

(8, 4)+5

Total = 17

 

Spoiler Test

Test

"Quote here?"

[samanyu10]

Dice Test:

d20+5

(16)+5

Total = 21

[samanyu10]

Dice Test:

d10

3

[samanyu10]

 

Testing 1 2 2 1

[ArchangelCo]

Dice Roll:

d20

3

[ArchangelCo]

Dice Roll:

4d6

2, 3, 2, 5

Total = 12

[ArchangelCo]

Dice Roll:

2d12+4

(9, 4)+4

Total = 17

[ArchangelCo]

Dice sneak:

d20+7

(3)+7

Total = 10

[suzaku]

Dice Roll:

4d20+6

(14, 11, 6, 16)+6

Total = 53

[suzaku]

Dice Acrobatics:

d20+4

(7)+4

Total = 11

[suzaku]

Dice Roll:

2d6+8	(6, 4)+8			Total = 18
3d10	8, 9, 4			Total = 21

[suzaku]

Dice Roll:

d6+3	(5)+3			Total = 8
d6+3	(4)+3			Total = 7
d6+3	(3)+3			Total = 6

[Treble83]

 

WIS

Dice Dagonet Stat Rolls:

4d6kh3

3, 4, 2, 6 (keeping 3,4,6)

Total = 13

CHA

Dice Dagonet Stat Rolls:

4d6kh3

6, 4, 3, 5 (keeping 4,5,6)

Total = 15

STR

Dice Dagonet Stat Rolls:

4d6kh3

3, 5, 2, 1 (keeping 2,3,5)

Total = 10

DEX

Dice Dagonet Stat Rolls:

4d6kh3

5, 1, 4, 6 (keeping 4,5,6)

Total = 15

CON

Dice Dagonet Stat Rolls:

4d6kh3

3, 5, 1, 5 (keeping 3,5,5)

Total = 13

INT

Dice Dagonet Stat Rolls:

4d6kh3

3, 6, 2, 1 (keeping 2,3,6)

Total = 11

Dice Dagonet HP:

2d8+11

(2, 1)+11

Total = 14

Dice Dagonet HP (Rerolling 1):

1d8+13

(7)+13

Total = 20

[stfranciswashere]

Dice Roll:

2d10+2

(4, 4)+2

Total = 10